Cambridge IGCSE Mathematics

Linear Equations

Solving equations & the straight line y = mx + c

The theory, at a glance

What is a Linear Equation?

An equation where the highest power of the variable is 1 — its graph is always a straight line.

ax + b = 0 a, b are constants · a ≠ 0

No x², √x or 1 x terms — just x to the power 1.

One variable → exactly one solution.

Solving by Balancing

Keep the equation balanced: whatever you do to one side, do to the other. Undo operations in reverse.

1 Move number terms away from x: 2x + 5 = 11 → 2x = 6 (−5 both sides)

2 Undo the multiply: x = 6 ÷ 2 = 3

3 Check: 2(3) + 5 = 11 ✓

RememberInverse operations: + ↔ − and × ↔ ÷. Always do the opposite.

Brackets & x on Both Sides

Expand brackets first, then collect the x-terms on one side.

3(x + 2) = 2x + 11

1 Expand: 3x + 6 = 2x + 11

2 x to one side: 3x − 2x = 11 − 6

3 Simplify: x = 5

Watch outMultiply every term inside a bracket: −2(x − 3) = −2x + 6, not −2x − 6.

The Line y = mx + c

m = gradient (steepness) · c = y-intercept (where it crosses the y-axis).

y = 2x + 1 → gradient 2, crosses y-axis at 1

m > 0 → uphill · m < 0 → downhill Bigger |m| → steeper line.

Finding the Gradient

From two points (x₁, y₁) and (x₂, y₂):

m = rise run = y₂ − y₁ x₂ − x₁

e.g. through (1, 3) and (4, 9):

m = 9 − 3 4 − 1 = 6 3 = 2

NoteSubtract the coordinates in the same order on top and bottom, or your sign will flip.

Worked Example

Find the equation of the line through (0, −1) with gradient 3, then solve where it meets y = 5.

1 Gradient m = 3, y-intercept c = −1 → y = 3x − 1

2 Set equal to 5: 3x − 1 = 5

3 Add 1: 3x = 6

4 Divide by 3: x = 2 → meets at (2, 5)

Exam tip Always substitute your answer back in: 3(2) − 1 = 5 ✓. One mark, every time.

Owlileo · IGCSE Mathematics (0580) · Algebra 2.5 — Linear Equations

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Practice, with the working

Three questions from the bank, each with its full solution.

1Easier
Solve 3x=213x = 21.
›Show solution
Divide both sides by 33: x=213=7x = \dfrac{21}{3} = 7.
2Medium
Solve 2x+13=x+52\dfrac{2x + 1}{3} = \dfrac{x + 5}{2}.
›Show solution
**Solution**
[M1] Cross-multiply: 2(2x+1)=3(x+5)2(2x + 1) = 3(x + 5).
[M1] Expand and collect: 4x+2=3x+154x + 2 = 3x + 15.
[A1] x=13x = 13. Check: 273=9=182\tfrac{27}{3} = 9 = \tfrac{18}{2}. ✓
**Answer:** x=13x = 13
3Harder
The angles of a triangle are x°x°, (2x−30)°(2x - 30)° and (x+50)°(x + 50)°.
›Show solution
**Part (a)**
_Find the value of xx._
[M1] Angles sum to 180°180°: x+2x−30+x+50=180x + 2x - 30 + x + 50 = 180.
[M1] 4x+20=1804x + 20 = 180, so 4x=1604x = 160.
[A1] x=40x = 40.
**Answer:** x=40x = 40
**Part (b)**
_What type of triangle is it? Give a reason._
[B1] x+50=90x + 50 = 90, so one angle is a right angle.
**Answer:** Right-angled — the angles are 40°40°, 50°50° and 90°90°.

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