IB Analysis & Approaches SL

Sequences & Series

IB MATHEMATICS · ANALYSIS & APPROACHES · SL

The theory, at a glance

Sequences & series with a common difference — nth term, sums & sigma notation. ✎

① Arithmetic Sequences

Each term is the previous one plus a fixed common difference d.

d = u n+1 − u n

Check it's arithmetic: the difference between any two consecutive terms is the same.

② The nth Term ✦ booklet

u n = u₁ + (n − 1)d

u₁ = first term · d = common difference.

It's just u₁ plus (n−1) jumps of size d — that's why it's n−1, not n.

Plots as a straight line (gradient d) — arithmetic = linear.

e.g. 4, 7, 10, 13, … → u₁=4, d=3 u n = 4 + (n−1)·3 = 3n + 1

③ Arithmetic Series (sum) ✦ booklet

A series is the sum of the first n terms. Two equivalent formulas:

S n = n / 2 [ 2u₁ + (n − 1)d ]

— use when you know d —

— use when you know the last term u n —

④ Sigma Notation Σ

Σ (sigma) is shorthand for "add them all up":

n=1

(2n + 1)

3 + 5 + 7 + 9

Bottom (n=1) = where to start · top (4) = where to stop.

Substitute n = 1, 2, 3, 4 into the rule, then add.

Number of terms = top − bottom + 1.

★ Worked example ✎

An arithmetic sequence has u₁ = 5 and d = 3.

Find u₁₀: u₁₀ = 5 + (10−1)·3 = 5 + 27 = 32

Exam tip!

Always find u₁ and d first — every arithmetic question unlocks from those two numbers.

Geometric

Sequences & series with a common ratio — nth term, sums & the sum to infinity. ✎

① Geometric Sequences

Each term is the previous one multiplied by a fixed common ratio r.

r = u n+1 / u n

u n = u₁ · r n−1

u₁ = first term · r = common ratio.

Multiply by r a total of (n−1) times to reach the nth term.

Grows exponentially (curved), not linearly.

e.g. 3, 6, 12, 24, … → u₁=3, r=2 u n = 3 · 2 n−1

③ Geometric Series (sum) ✦ booklet

Sum of the first n terms (r ≠ 1) — two equivalent forms:

S n = u₁(r n − 1) / r − 1

— best when r > 1 —

S n = u₁(1 − r n ) / 1 − r

— best when r < 1 (keeps it positive) —

④ Sum to Infinity S∞ ✦ booklet

S ∞ = u₁ / 1 − r

only converges when |r| < 1

When terms shrink, the total approaches a finite limit. Picture ½ + ¼ + ⅛ + … filling one whole square:

⑤ Compound Interest ✦ booklet

Money growing by a fixed % is a geometric sequence:

r = annual interest rate (%) · n = years.

k = compounding periods per year (12 = monthly).

A geometric sequence has u₁ = 8 and r = ½.

Find u₄: u₄ = 8 · (½)³ = 8 · ⅛ = 1

Sum to infinity? |½| < 1 ✓ so it converges:

1 − ½

Always check |r| < 1 before using S∞ — if not, the sum diverges and has no finite value.

made for revision · IB AA SL · keep it by your desk ✦

Download the PDF cheatsheet

One page, free — along with nine others.

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Practice, with the working

Three questions from the bank, each with its full solution.

1Easier
True or False: In an arithmetic sequence, consecutive terms always have a constant ratio.
›Show solution
False. An arithmetic sequence has a constant *difference* between consecutive terms. A constant *ratio* describes a geometric sequence.
2Medium
The sum of the first nn terms of a sequence is given by Sn=n2+6nS_n = n^2 + 6n. Find an expression for the nnth term, unu_n.
›Show solution
**Solution**
[M1] Use un=Sn−Sn−1u_n = S_n - S_{n-1} (for n≥2n \ge 2): Sn−1=(n−1)2+6(n−1)=n2+4n−5S_{n-1} = (n-1)^2 + 6(n-1) = n^2 + 4n - 5.
[A1] un=(n2+6n)−(n2+4n−5)=2n+5u_n = (n^2 + 6n) - (n^2 + 4n - 5) = 2n + 5. (Check: u1=S1=7=2(1)+5u_1 = S_1 = 7 = 2(1)+5.)
**Answer:** un=2n+5u_n = 2n + 5
3Harder
A theatre has 2424 seats in the front row, and each row behind has 33 more seats than the row in front. If there are 1818 rows, how many seats are there in total?
›Show solution
Here u1=24u_1 = 24, d=3d = 3, n=18n = 18.
S18=182(2×24+17×3)=9(48+51)=9×99=891S_{18} = \dfrac{18}{2}\big(2\times 24 + 17\times 3\big) = 9(48 + 51) = 9\times 99 = 891 seats.

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