IB Analysis & Approaches SL
Sequences & Series
IB MATHEMATICS · ANALYSIS & APPROACHES · SL
The theory, at a glance
Sequences & series with a common difference — nth term, sums & sigma notation. ✎
① Arithmetic Sequences
Each term is the previous one plus a fixed common difference d.
d = u n+1 − u n
Check it's arithmetic: the difference between any two consecutive terms is the same.
② The nth Term ✦ booklet
u n = u₁ + (n − 1)d
u₁ = first term · d = common difference.
It's just u₁ plus (n−1) jumps of size d — that's why it's n−1, not n.
Plots as a straight line (gradient d) — arithmetic = linear.
e.g. 4, 7, 10, 13, … → u₁=4, d=3 u n = 4 + (n−1)·3 = 3n + 1
③ Arithmetic Series (sum) ✦ booklet
A series is the sum of the first n terms. Two equivalent formulas:
S n = n / 2 [ 2u₁ + (n − 1)d ]
— use when you know d —
— use when you know the last term u n —
④ Sigma Notation Σ
Σ (sigma) is shorthand for "add them all up":
n=1
(2n + 1)
3 + 5 + 7 + 9
Bottom (n=1) = where to start · top (4) = where to stop.
Substitute n = 1, 2, 3, 4 into the rule, then add.
Number of terms = top − bottom + 1.
★ Worked example ✎
An arithmetic sequence has u₁ = 5 and d = 3.
Find u₁₀: u₁₀ = 5 + (10−1)·3 = 5 + 27 = 32
Exam tip!
Always find u₁ and d first — every arithmetic question unlocks from those two numbers.
Geometric
Sequences & series with a common ratio — nth term, sums & the sum to infinity. ✎
① Geometric Sequences
Each term is the previous one multiplied by a fixed common ratio r.
r = u n+1 / u n
u n = u₁ · r n−1
u₁ = first term · r = common ratio.
Multiply by r a total of (n−1) times to reach the nth term.
Grows exponentially (curved), not linearly.
e.g. 3, 6, 12, 24, … → u₁=3, r=2 u n = 3 · 2 n−1
③ Geometric Series (sum) ✦ booklet
Sum of the first n terms (r ≠ 1) — two equivalent forms:
S n = u₁(r n − 1) / r − 1
— best when r > 1 —
S n = u₁(1 − r n ) / 1 − r
— best when r < 1 (keeps it positive) —
④ Sum to Infinity S∞ ✦ booklet
S ∞ = u₁ / 1 − r
only converges when |r| < 1
When terms shrink, the total approaches a finite limit. Picture ½ + ¼ + ⅛ + … filling one whole square:
⑤ Compound Interest ✦ booklet
Money growing by a fixed % is a geometric sequence:
r = annual interest rate (%) · n = years.
k = compounding periods per year (12 = monthly).
A geometric sequence has u₁ = 8 and r = ½.
Find u₄: u₄ = 8 · (½)³ = 8 · ⅛ = 1
Sum to infinity? |½| < 1 ✓ so it converges:
1 − ½
Always check |r| < 1 before using S∞ — if not, the sum diverges and has no finite value.
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