IB Analysis & Approaches SL
Sine & Cosine Rule
IB MATHEMATICS · ANALYSIS & APPROACHES · SL · TOPIC 3.3
The theory, at a glance
Solving any triangle — not just right-angled ones. Plus the ambiguous case. ✎
① Labelling a Triangle
lower case
Get this right first — every formula on this sheet depends on the side sitting opposite its angle.
② Sine Rule ✦ formula booklet
a / sin A = b / sin B = c / sin C
Use it when you have a matching pair:
2 angles + 1 side (AAS) → find a side.
2 sides + 1 opposite angle (SSA) → find an angle.
Looking for an angle? Flip it over — use sin A / a = sin B / b to keep the unknown on top.
③ Cosine Rule ✦ formula booklet
to find a SIDE
a² = b² + c² − 2bc · cos A
to find an ANGLE
cos A = b² + c² − a² / 2bc
Use it when the sine rule can't start:
2 sides + the angle BETWEEN them (SAS) → find the 3rd side.
All 3 sides (SSS) → find any angle.
−2bc cos A
b², c²
④ Which Rule? — Decision Table
SSS — 3 sides
Cosine (angle form)
SAS — angle between
Cosine (side form)
SSA — non-included
Sine rule (ambiguous!)
right angle + 2 things
SOH CAH TOA
Quick test: can you see a side and its opposite angle both known? → sine rule. If not → cosine rule.
⑤ The Ambiguous Case (SSA)
When you use the sine rule to find an angle, there can be two valid answers.
same a, same c, same A — two different triangles
if θ works, so does 180° − θ
(because sin θ = sin(180° − θ))
Your GDC only ever gives the acute answer.
Check it: add your angle to the known one. If the total is < 180°, that option is valid.
Only happens when finding an angle with the sine rule — never with the cosine rule.
★ Worked example ✎
In triangle ABC, b = 7 cm, c = 9 cm and A = 62°. Find a, then find angle B.
Spot the type:
a² = 7² + 9² − 2(7)(9)cos 62° = 49 + 81 − 126 cos 62° ≈ 130 − 59.15 = 70.85
a = 70.85 ≈ 8.42 cm
Check: 62 + 47.2 = 109.2°, so C ≈ 70.8°. All three add to 180° ✓
Tip!
Don't work out 2bc and cos A separately then subtract wrongly — put the whole line into the GDC at once. And never round before the final answer.
Area & Applications
Area of a triangle with sine, bearings & multi-triangle problems. ✎
① Area of a Triangle ✦ formula booklet
Area = ½ · a · b · sin C
the angle C sits BETWEEN sides a and b
② Area — Which Version?
2 sides + included angle
→ straight into ½ab sin C.
base + perpendicular height
→ the old ½ × base × height.
all 3 sides (SSS)
→ cosine rule for an angle first, then ½ab sin C.
③ Bearings
Measured clockwise from North, always written with three digits.
Write 055°, not 55°.
Back bearing (B to A) = bearing ± 180°.
Draw a North line at every point, then hunt for the triangle's interior angles.
④ Two-Triangle Problems
Find the shared side — it's the bridge between the two triangles.
Solve the triangle that has enough information first.
Carry the shared side into the second triangle.
Use angles on a straight line (180°) and angles at a point (360°) to fill gaps.
A triangular field has sides 12 m, 15 m and 20 m. Find its area.
SSS — no angle yet, so find one with the cosine rule. Let a = 20, b = 12, c = 15.
cos A = 12² + 15² − 20² / 2(12)(15) = −31 / 360
(obtuse — fine!)
Area = ½(12)(15) sin 94.9° ≈ 89.7 m²
negative cos
two sides that touch it
Download the PDF cheatsheet
One page, free — along with nine others.
↓ PDFPractice, with the working
Three questions from the bank, each with its full solution.
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